x^2=(53)^2+(5)^2

Solution for x^2=(53)^2+(5)^2 equation:

x^2=(53)^2+(5)^2

We move all terms to the left:

x^2-((53)^2+(5)^2)=0

We add all the numbers together, and all the variables

x^2-2834=0

a = 1; b = 0; c = -2834;
Δ = b2-4ac
Δ = 02-4·1·(-2834)
Δ = 11336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11336}=\sqrt{4*2834}=\sqrt{4}*\sqrt{2834}=2\sqrt{2834}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2834}}{2*1}=\frac{0-2\sqrt{2834}}{2}
=-\frac{2\sqrt{2834}}{2}
=-\sqrt{2834}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2834}}{2*1}=\frac{0+2\sqrt{2834}}{2}
=\frac{2\sqrt{2834}}{2}
=\sqrt{2834}
$